I think you'll have to post your launch file, and probably a "rosparam get MY_NAMESPACE". It could be your configuration isn't set up properly.
Hi Kevin,I had gotten that far, but by what name do I then access the parameter from my python source? Neither rospy.get_param('port') nor rospy.get_param('~port') seem to work.M.On 14 July 2010 15:53, Kevin Watts <watts@willowgarage.com> wrote:That's not the correct syntax for private parameters. Your example puts them into the same namespace as the node, but not the private namespace.
You can find full details here:
http://www.ros.org/wiki/roslaunch/XML/param
For your code, it might look like:
<node pkg="something" ... >
<param name="port" value="/dev/ttyUSB0" />
</node>On Wed, Jul 14, 2010 at 12:41 PM, Mike Purvis <mpurvis@clearpathrobotics.com> wrote:
_______________________________________________Hi everyone,My current launch file structure is like so:<launch><env name="PYTHONPATH" value="$(env PYTHONPATH)" /><group ns="clearpath/robots/$(optenv ID default)" clear_params="true"><param name="port" value="$(optenv CPR_SERIAL_PORT /dev/ttyUSB0)" /><param name="turn_radius" value="0.4" />...<node pkg="clearpath_horizon" type="horizon.py" name="$(anon horizon)" output="screen" /><node pkg="clearpath_2dnav" type="simple.py" name="$(anon nav)" output="screen" />....</group></launch>And then inside of horizon.py, I am able to access the parameter with rospy.get_param('port'). However, that parameter is really not relevant to any node except horizon.py. From my reading of the documentation, I should be able to make it private by putting the <param> tag inside the relevant node tag, and then calling it with rospy.get_param('~port'). However, this doesn't seem to work---I consistently just get the default parameter.What am I doing wrong?Thanks.
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